Ninfa Asby: The mass falls at constant acceleration. Using distance = half acceleration time time squared, we get the acceleration is 0.41 ms-2.That gives us a final speed of the mass of v = half acceleration times time squared of 0.82 ms-1.The lost grav potential energy is therefore E=mgh=16.0884 joules (with g=9.81ms-2)The ke of the block using the above speed is E= half mass times speed squared = 0.6724JSo therefore using conservation of energy the remaining energy gained is stored as kinetic energy in the rotation of the cylinder. KE of cylinder = 15.416 joules.The formula for KE of a cylinder is E = half (mass) times (moment of inertia) times (rotational velocity) squared.Moment of inertia for a cylinder is mass times radius squared.Rotational velocity is the velocity of the block divided by the radius.Plugging those into the formula above gives cylinder mass of 45.85366kg, as the radius terms cancel....Show more
Maynard Phoubandith: EDIT 1 - I'm not asking for! the WEIGHT of the block but rather the MASS of the cylinder in which the string is wrapped around.
Sherita Gallati: [2.0 kg * 9.8 m/s^2 ]
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